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9x^2=35x+4
We move all terms to the left:
9x^2-(35x+4)=0
We get rid of parentheses
9x^2-35x-4=0
a = 9; b = -35; c = -4;
Δ = b2-4ac
Δ = -352-4·9·(-4)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-37}{2*9}=\frac{-2}{18} =-1/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+37}{2*9}=\frac{72}{18} =4 $
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